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• Kinematics
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• Basic motions

Uniform Motion

It is a movement in which the scalar speed is constant and different from zero $$v(t) = v_0 = \mbox{constant} \ne 0$$. The position as a fuction of time, for this movement, is: $$s(t) = s_0 + v_0 t.$$

The figure below illustrates the graph $$s \times t$$ of this movement, which, in this case, is always a straight line, that increases with time if $$v_0 \gt 0$$ and decreases with time if $$v_0 \lt 0$$. Graph $$s \times t$$ to $$v=constant\gt0$$. In the uniform motion, where the speed is positive and does not change, the graphic of the position versus time is a straight line (red line). The slope of this straight line (blue slope) is related to the speed, greater speed means greater slope.

Uniformly accelerated motion

Uniformly varying motion is the movement in which scalar acceleration is constant and nonzero, $$a(t)=\mbox{constant} \ne 0$$.

The functions for this type of movement are:

The position as a fuction of time
$$s(t) = s_0 + v_0 t + a \frac{t^2}{2}.$$
The speed as a fuction of time
$$v(t) = v_0 + a t.$$
The Torricelli's equation
$$v^2 = v_0^2 + 2 a \Delta s,$$ and, in this case, $$v$$ is related to $$\Delta s$$.
In all these cases, $$a$$, $$s_0$$ and $$v_0$$ are constant, i.e., does not change in the time interval of interest, different from $$s(t)$$ and $$v(t)$$ that are always changing.

Graphics and interpretations

The graphics for this movement and their interpretations are presented below.

Space $$\times$$ time $$(a > 0)$$
Space $$\times$$ time $$(a < 0)$$
Speed $$\times$$ time $$(a > 0)$$ The area $$A$$ under the graphic curve $$v \times t$$, yellow region, is the distance traveled by the object from $$t_0$$ to $$t_1$$. In the same graph, the acceleration is given by the slope of the line, therefore, if the acceleration was negative, the graph would be a straight line inclined downwards. STUDY PHYSICS ANYTIME ANYWHERE Dynamic Exams Differentiated Content Top approval rate